Why printf does not print “operator” on console?

Question

Bottom printf() does not print operator variable on console. But only number1 and number2 are printed. What can be the cause?

Output : How much is 2 7 ?

char operator;

    switch(type){   
        case 1: 
        operator=='+';
        result=number1+number2;
        break;
        case 2: operator=='-';
        result=number1-number2;
        break;
        case 3: operator=='*';
        result=number1*number2;
        break;
        case 4: 
        operator=='/';
        result=number1/number2;
        break;

    }       
    printf("How much is %d %c %d ?",number1, operator, number2);

Answer 1

operator=='+';

should be

operator='+';

The same for the other operators

The assignment in c is with = only

The equal comparison is with == example if(operator == '+')

Answer 2

== is equality operator, it doen't assign a value just checks if the two sides are equal.

You must use the assignment operator = .

For example:

operator='/'

Answer 3

Instead of using of the assignment operator = , you are using the comparison operator == .

Thus after the operator=='+' the value of the operator remains unchanged.