How to check if an object in a list has a certain property

Question

We have some objects with properties

class my_object:
    def __init__(self, type, name):
        self.type = type
        self.name = name

And a list which contains many object with different type and name values.

What I need is a comprehension which does something like:

if my_object.type == 'type 1' in object_list:
    object_list.remove(all objects with name == 'some_name')

Answer 1

我认为您正在寻找：

object_list = filter(lambda x: x.name != 'some_name', object_list)

Answer 2

I think what you need is :

if any(obj.type == 'type 1' for obj in object_list):
    object_list = [obj for obj in object_list if obj.name != 'some_name']

Answer 3

if hasattr(my_object,"some_attribute") : doSomething()

尽管就您而言，我认为您想要

filter(lambda x:not hasattr(x,"name") or x.name != "some_name",my_list_of_objects)

Answer 4

You could do:

def remove_objects(obj_list,*args,**kwargs):
    for n_count,node in enumerate(obj_list[::]):
        del_node=False
        for k,v in kwargs.items():
            if hasattr(node,str(k)):
                if getattr(node,str(k))==v:
                    del_node=True
                    break
        if del_node:
            del obj_list[n_count]

And use it like:

class HelloWorld(object):
    lol="haha"
my_list_of_objects=[HelloWorld for x in range(10)]
remove_objects(my_list_of_objects,lol="haha")