Validating XSD itself

Question

Could anyone please tell me how to validate an XSD file itself (not XML against XSD)? I have checked many forums and sites (including SO) and most of them refers some or the other online validator. But this is not a one-time check for us. Our application involves an XSL transformation using an XSD, so we need to determine whether the XSD to be used is itself in a valid format or not, as in, all the tags match, with a starting and a closing one. Certain tags aren't allowed as a child tag, etc. That's why we need a proper java code to achieve the same.

Any help would be highly appreciated.

Answer 1

You can validate an XSD file against the w3 XSD schema that can be found here .

Use the same validation techniques you validate any other XML file with an XSD file, only the source document would be your XSD file.

Answer 2

You can validate your XSD online here .

Just copy and paste your XSD here and click on validate Schema , it will give you the result.

Answer 3

You can try javax.xml.validation package

SchemaFactory f = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema s = f.newSchema(new File("1.xsd"));

Schema.newSchema() API

Parses the specified File as a schema and returns it as a Schema

Answer 4

您可以使用xmllint：

xmllint --noout --dtdvalid http://www.w3.org/2001/XMLSchema.dtd my-schema.xsd