Count NULL Values from multiple columns with SQL

Question

I have 3 columns let say A , B , and C . I need to count the NULL values in each column.

For example:

 A  | B  | C
-------------
1   |NULL| 1
1   | 1  | NULL
NULL| 1  | 1
NULL|NULL| 1

Should output:

 A  |  B  |  C
---------------
 2  |  2  |  1

I've tried count, sum, sub-queries but nothing has worked for me yet. Any input would be appreciated!

Answer 1

SELECT COUNT(*)-COUNT(A) As A, COUNT(*)-COUNT(B) As B, COUNT(*)-COUNT(C) As C
FROM YourTable; 

Answer 2

You can use an aggregate function with a CASE expression:

select 
  sum(case when a is null then 1 else 0 end) A,
  sum(case when b is null then 1 else 0 end) B,
  sum(case when c is null then 1 else 0 end) C
from yt

See Demo

Answer 3

For SQL SERVER you can use the following:

SET NOCOUNT ON
DECLARE @Schema NVARCHAR(100) = '<Your Schema>'
DECLARE @Table NVARCHAR(100) = '<Your Table>'
DECLARE @sql NVARCHAR(MAX) =''
IF OBJECT_ID ('tempdb..#Nulls') IS NOT NULL DROP TABLE #Nulls

CREATE TABLE #Nulls (TableName sysname, ColumnName sysname , ColumnPosition int ,NullCount int , NonNullCount int)

 SELECT @sql += 'SELECT  '''+TABLE_NAME+''' AS TableName , '''+COLUMN_NAME+''' AS ColumnName,  '''+CONVERT(VARCHAR(5),ORDINAL_POSITION)+''' AS ColumnPosition, SUM(CASE WHEN '+COLUMN_NAME+' IS NULL THEN 1 ELSE 0 END) CountNulls , COUNT(' +COLUMN_NAME+') CountnonNulls FROM '+QUOTENAME(TABLE_SCHEMA)+'.'+QUOTENAME(TABLE_NAME)+';'+ CHAR(10)
 FROM INFORMATION_SCHEMA.COLUMNS
 WHERE TABLE_SCHEMA = @Schema
 AND TABLE_NAME = @Table

 INSERT INTO #Nulls 
 EXEC sp_executesql @sql

 SELECT * 
 FROM #Nulls

 DROP TABLE #Nulls

you will receive a result set with the count of Null values and non null values in each column of you table

Answer 4

SELECT
(SELECT count(*) FROM my_table WHERE A is NULL) as A,
(SELECT count(*) FROM my_table WHERE B is NULL) as B,
(SELECT count(*) FROM my_table WHERE C is NULL) as C

Answer 5

select
    sum(case when a is null then 1 else 0 end) as a_null_count,
    sum(case when b is null then 1 else 0 end) as b_null_count,
    sum(case when c is null then 1 else 0 end) as c_null_count
from table

Answer 6

I am very late to this, but if you don't want to manually list out all the column names and still want to get a table, you can do this in SQL Server (Just replace testTable with your actual table):

--Creates the table the poster wanted

CREATE TABLE testTable (A int, B int, C int)
INSERT INTO testTable (A, C) VALUES (1,1)
INSERT INTO testTable (A, B) VALUES (1,1)
INSERT INTO testTable (B, C) VALUES (1,1)
INSERT INTO testTable (C) VALUES (1)

--Creates the output table which will consist of each column name and the amount of nulls

CREATE TABLE ColumnNames (
    ID int IDENTITY(1,1) PRIMARY KEY,
    [name] varchar(max),
    nullAmount int
)

INSERT INTO ColumnNames ([name]) 
SELECT [name] FROM sys.columns WHERE object_id = OBJECT_ID('dbo.testTable')

DECLARE @columnIndex INT = 1

WHILE @columnIndex <= ( SELECT COUNT(*) FROM dbo.ColumnNames )
BEGIN
    DECLARE @colName nvarchar(max) = (SELECT [name] FROM ColumnNames WHERE ID = @columnIndex)
    EXEC('SELECT ' + @colName + ' INTO colTable FROM testTable')

    DECLARE @SQL nvarchar(max) = N'UPDATE ColumnNames SET nullAmount = (SELECT COUNT(1) - COUNT(' + quotename(@colName) + ') FROM colTable) WHERE ID = @columnIndex'
    EXEC SP_EXECUTESQL @SQL, N'@columnIndex int', @columnIndex 

    DROP TABLE colTable
    SET @columnIndex = @columnIndex + 1
END

--Select the output table and get null info
SELECT * FROM ColumnNames