i have this table called records:
+---------------------+---------------------+
| date_returned | date_borrowed |
+---------------------+---------------------+
| 2013-05-31 09:27:38 | 2013-05-31 08:48:14 |
| 2013-05-31 09:22:27 | 2013-05-31 08:53:06 |
| 2013-05-31 09:27:38 | 2013-05-31 09:22:35 |
| 2013-05-31 15:27:02 | 2013-05-31 09:22:39 |
| 2013-05-31 15:27:02 | 2013-05-31 10:04:22 |
+---------------------+---------------------+
i want to include the total hours as another column in the result. i read the manual but datediff seemed to be vague and just returns the difference as days.
Try:
SELECT
TIMEDIFF(date_borrowed, date_returned) AS diff
FROM
tablename
SELECT
HOUR(TIMEDIFF(date_borrowed, date_returned)) as TotalHours
FROM
tablename
How about converting to timestamp values - that'll let you subtract to get the difference in seconds, and you can manipulate as much as you want from there.
SELECT
date_returned,
date_borrowed,
(UNIX_TIMESTAMP(date_returned) - UNIX_TIMESTAMP(date_borrowed)) / 3600 AS hours
FROM tablename
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