简体   繁体   中英

How to make asynchronous call with timeout

I want to make an asynchronous call in C++ with timeout, meaning I want to achieve sth like that.

AsynchronousCall(function, time);
if(success)
    //call finished succesfully
else
    //function was not finished because of timeout

EDIT : Where function is a method that takes a lot of time and I want to interrupt it when it takes too much time. I' ve been looking for how to achieve it and I thinki boost::asio::deadline_timer is way to go. I guess calling timer.async_wait(boost::bind(&A::fun, this, args)) is what I need, but I do not know how to find if the call was success or was aborted due to timeout.

EDIT: after the answer from ForEveR my code now looks like this.

    boost::asio::io_service service;
boost::asio::deadline_timer timer(service);
timer.expires_from_now(boost::posix_time::seconds(5));
timer.async_wait(boost::bind(&A::CheckTimer, this, boost::asio::placeholders::error));
boost::thread bt(&A::AsynchronousMethod, this, timer, args);  //asynchronous launch

void A::CheckTimer(const boost::system::error_code& error)
{
if (error != boost::asio::error::operation_aborted)
{
    cout<<"ok"<<endl;
}
// timer is cancelled.
else
{
    cout<<"error"<<endl;
}
}

I wanted to pass the timer by reference and cancel it in the end of asynchronous method, but I got an error that I cannot access private member declared in class ::boost::asio::basic_io_object.

Maybe using the deadline timer is not that good idea ? I would really appreciate any help. I am passing the timer to the function, because the method that calls the asynchronous method is asynchronous itself and thus I cannot have one timer for whole class or sth like that.

You should use boost::asio::placeholders::error

timer.async_wait(boost::bind(
&A::fun, this, boost::asio::placeholders::error));

A::fun(const boost::system::error_code& error)
{
   // timeout, or some other shit happens
   if (error != boost::asio::error::operation_aborted)
   {
   }
   // timer is cancelled.
   else
   {
   }
}

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM