I have a web page written in php where i get some info about the user from his linked in profile, thanks to linked in API. It gives me the following json object. with :
$user = json_decode($response);
method i decode the following json object into $user object.
{ "firstName": "Tolga", "lastName": "Evcimen", "skills": { "_total": 2, "values": [ { "id": 1, "skill": {"name": "Microsoft Office"} }, { "id": 2, "skill": {"name": "Microsoft Excel"} } ] } }
what i can't is to work with these values, my php knowledge is a little low, that's why i don't know how to read skills or anything else. The only thing I could read so far is :
$user->firstName , $user->lastName
but I can't get the rest with same approach :(
$user->skills->values[1]->skill->name, or $user->skills->_total
please give me some information about these things
This works:
echo $user->firstName;
echo $user->skills->values[0]->id;
echo $user->skills->values[0]->skill->name;
Results:
Tolga
1
Microsoft Office
Test it on PHP fiddle: http://phpfiddle.org/main/code/x18-z6f
I had no problem with this, maybe post a code example so we can see where you went wrong.
$user->skills->values[1]->skill->name
Example:
<?php
$response = '{
"firstName": "Tolga",
"lastName": "Evcimen",
"skills": {
"_total": 2,
"values": [
{
"id": 1,
"skill": {
"name": "Microsoft Office"
}
},
{
"id": 2,
"skill": {
"name": "Microsoft Excel"
}
}
]
}
}';
$user = json_decode($response);
var_dump($user->skills->values[1]);
?>
Output:
object(stdClass)#5 (2) {
["id"]=>
int(2)
["skill"]=>
object(stdClass)#6 (1) {
["name"]=>
string(15) "Microsoft Excel"
}
}
thanks a lot, it turned out I made some other mistakes in the code, instead of echo I used print, and kinda mixed it up in a bad way. thats why I couldn't achive the right behaviour in code.
$user = fetch('GET', '/v1/people/~:(firstName,lastName,skills)');
print "\n <\br> Hello $user->firstName $user->lastName.";
print " $user->skills->values[0]->skill->name";
echo $user->skills->values[0]->skill->name;
exit;
doesn't work :)
echo "\n <\br> Hello $user->firstName $user->lastName.";
echo $user->skills->values[0]->skill->name;
works fine.
Grateful for your concerns.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.