I'm trying to call the following function but I cannot figure out how to fill in the third parameter.
RSA* PEM_read_RSAPrivateKey(FILE *fp, RSA **x, pem_password_cb *cb, void *u);
Looking up pem_password_cb I find:
typedef int pem_password_cb(char *buf, int size, int rwflag, void *userdata);
I understand typedefs with function pointers, but this doesn't appear to be a function pointer. Can anyone help me with an example of what goes in the third parameter? I don't have access to the implementation of pem_password_cb.
You are right: this is a typedef to a function type, not to a pointer. But the function PEM_read_RSAPrivateKey
receives a pointer to it: pem_password_cb *cb
.
The usage is just like any other function pointer:
int some_func(char *buf, int size, int rwflag, void *userdata) {
return 0;
}
PEM_read_RSAPrivateKey(NULL, NULL, some_func, NULL);
/* Your function definition is like this. */
int my_pem_password_cb_fun(char *buf, int size, int rwflag, void *userdata)
{
/* your stuff */
}
You pass my_pem_password_cb_fun as 3rd parameter.
pem_password_cb is just a typedef and it is not implementation. You need to implement a function [my_pem_password_cb_fun()] that takes parameters as given in typedef.
It's a typedef for a function.
But note that the argument, pem_password_cb *cb
is a pointer. So the argument really is a function pointer.
So you just need to implement a function that matches the int pem_password_cb(char *buf, int size, int rwflag, void *userdata);
signature.
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