Say i have five variables a,b,c,d and e which are all assigned a random number from five different ranges corresponding to to the five variables a to e.
Is there a way to assign a sixth variable say x, that chooses a random number from a range with upper value equal to the total of a+b+c+d+e?
for example, say :-
a=5 (range 0-10)
b=1043 (range 0-2000)
c=37 (range 0-38)
d=2 (range 0-100)
e=20 (range 5-30)
then x = (random number) (range 5- 1107)
Thanks for any assistance
You can use
Min + (int)(Math.random() * ((Max - Min) + 1))
Where Min = a and Max = a+b+c+d+e
From java.util.Random
:
Random rand = new Random();
rand.nextInt(X);
//returns an `int` in range: [0,X)
So, if you have a
, b
, ..., n
, to get a number in between 0 and the sum of the variables, we do:
rand.nextInt(a + b + ... + n + 1); //returns an `int` in range [0, sum(a,b,...,n)]
As other users have suggested, you can also use Math.random()
; however, Math.random()
returns a double
in range: [0,1)
. So, if you have min = 0
, max = 9
, and want a number between [0,9]
, then you need:
Min + (int)(Math.round((Math.random() * (Max - Min))))
//need to cast to int since Math.round(double returns a long)
or you could do:
Min + (int)(Math.random() * (Max - Min + 1))
Edit: I missunderstood your problem, but you just need to sum each var and do the same thing. Some answers already showed that.
It is just a algorithm problem.
int lra = 0; // lower range of a
int ura = 10; // upper range of a
int lrb = 0;
int urb = 2000;
// a couple of ranges for each var...
int a = lra + ((int) (Math.random() * (ura - lra)));
// the same for each var...
int lrs = lra + lrb + ...; // sum of lower ranges...
int urs = ura + urb + ...; // sum of upper ranges
int x = lrs + ((int) (Math.random() * (urs - lrs)));
Something like this should do the job
Random generator = new Random();
generator.setSeed(System.currentTimeMillis());
long range = a+b+c+d+e;
long fraction = (long)(range * generator.nextDouble());
randomNumber = (int)(fraction);
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