Python: “if closest to 1”

Question

I am doing some calculations on a dictionary. But the important thing is I want to make a if-condition that kind of says

"if x has a value that is closer to 1 (or equal to 1) than variable "

kind of hard to explain, but hope you understand.

Answer 1

You can use absolute value :

if abs(x-1) < abs(variable-1):
    ...

since absolute value of x-1 is the distance between x and 1 , and similarly absolute value of variable-1 is the distance between variable and 1 .