I have encountered a problem when trying to insert a "#" sign into a cell using script (that is triggered to run when a submission comes from a form).
I have tried to do it this way:
somecell.setFormula('=HYPERLINK("http://www.some.link/some/'+var+'#1a2b3c","'+var+'")');
So the output should be:
=HYPERLINK("http://www.some.link/some/1234#1a2b3c","1234")
But it is always inserted as only (no # and the rest of link after the sign)
=HYPERLINK("http://www.some.link/some/1234","1234")
There are no errors reported during execution. How should I put the sign into the script so it will be inserted into the formula? I had tried using ...1234(backslash)#1a... but it does not work.
Edit How does the script work (in short): firstly, sheet receives a form submission with an URL as one of the entries. Then, the script cuts off part of the link (using .split('/') and then .pop() to get the last element of the array that .split created) and the variable extracted this was is used in the .setFormula seen above as var .
Also, I have tried again; backslash does not work - everything after (and including) # is deleted.
You need to include a backslash to escape the character:
function addlink() {
var somecell = SpreadsheetApp.getActiveSpreadsheet().getRange('F2');
var blah = "123";
somecell.setFormula('=HYPERLINK("http://www.some.link/some/'+blah+'\#1a2b3c","'+blah+'")');
// ^^^
}
I tried your example like this :
function test(){
var sh = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var xx = '1234'
sh.getRange('A2').setFormula('=HYPERLINK("http://www.some.link/some/'+xx+'#1a2b3c","'+xx+'")');
}
and I get the expected result
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