Which is a simple method / regular expression to extract the links from a BBcode [code]...[/code] section? All links begin with http:// and end with \\n OR a [/code] tag, maybe some space or other whitespace characters at the end.
One [code] section can contains multiple links / code tag:
[code]http://example1.com
http://example2.com
http://example3.com
[code]
and sometimes multiple consecutive [code] sections can also occur:
[code]http://example4.com
http://example5.com [/code]
[code]http://example6.com[/code]
[code]
http://example7.com
http://example8.com[/code]
I would like to get all the links from such a section defined above in a simple flattened array, but I am unable to solve the right regular expression for the scan method.
Try this one:
data = '[code]http://example4.com
http://example5.com [/code]
[code]http://example6.com[/code]
[code]
http://example7.com
http://example8.com[/code]'
p data.split(/\[\/*code\]/)
.flat_map{|el| el.split(/\s+/)}
.reject(&:empty?)
Output:
#=> ["http://example4.com", "http://example5.com", "http://example6.com", "http://example7.com", "http://example8.com"]
You can try this:
Test string:
bbcode = <<EOF
[code] xxxxx
xxxxx
http://example1.com
http://example2.com
http://notme.org abcd
http://example3.com
[/code]
[code]xxxx[/code]
http://notme.com
[code]http://example4.com
http://example5.com[/code]
[code]http://example6.com [/code]
[code]
http://example7.com
http://example8.com[/code]
EOF
Regex:
pattern = Regexp.new('
# Definitions
(?<url> http://[^\[\s]++ ){0}
(?<open> \[code\] ){0}
(?<close> \[/code\] ){0}
(?<ws> [^\S\n]++ ){0}
(?<other> \g<ws>?+
(?> (?!\g<url>) | \g<url> \g<ws> )
[^\[\n]++ ){0}
(?<end> \g<ws>?+ (?> \n | \g<close> ) ){0}
# Pattern
(?> \g<open> | \G (?<! \g<close> ) )
(?> \g<other>?+ \n++ )* \g<ws>?+ \g<url> \g<end> ',
Regexp::EXTENDED | Regexp::IGNORECASE)
bbcode.scan(pattern) do |link, tag|
puts "#{link}\n"
end
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