Relate MySQL table to a specific value
Question
What I want to do is quite simple: I want to recover data from a database, only where the ID of the first table (stored in session) is similar to the ID of the second table. My code is this one below. The only problem: the present code gives me the following error:
Query is invalid: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.' at line 1
What am I doing wrong? Thanks for your help!
<?php include "base.php"; ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1- strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<?php
//We check if the user is logged
if(isset($_SESSION['Username']))
{
?>
<?php
//query
$query = mysql_query("select TitreEvent, DescriptionEvent from users_event where ID = .$_SESSION [id].") or die ('Query is invalid: ' . mysql_error());
//write the results
while ($row = mysql_fetch_array($query)) {
echo $row['TitreEvent'] . " " . $row['DescriptionEvent'] . "";
// close the loop
}
?>
<div class="message">To access this page, you must be logged.<br />
<a href="http://www.groupe90.webege.com/index.php">Log in</a></div>
<?php
}
?>
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</body>
</html>
2 answers
solution1
2 ACCPTED 2013-07-25 18:10:34
Your PHP is broken where you build the query string:
$query = mysql_query("select [...snip...] where ID = .$_SESSION [id].") or die ('Query is invalid: ' . mysql_error());
^-- here
you never ended the string, so the $_SESSION portion is actually part of the query string, producing
where ID = Array [id].
It should be
where ID = " . $_SESSION['id']) ...
solution2
0
$query = mysql_query("select TitreEvent, DescriptionEvent from users_event where ID = '$_SESSION[id]'") or die ('Query is invalid: ' . mysql_error());
Try the above code
You have to put your condition in single quote
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