I want to read huge text file line by line (and stop if a line with "str" found). How to check, if file-end is reached?
fn = 't.log'
f = open(fn, 'r')
while not _is_eof(f): ## how to check that end is reached?
s = f.readline()
print s
if "str" in s: break
There's no need to check for EOF in python, simply do:
with open('t.ini') as f:
for line in f:
# For Python3, use print(line)
print line
if 'str' in line:
break
It is good practice to use the
with
keyword when dealing with file objects. This has the advantage that the file is properly closed after its suite finishes, even if an exception is raised on the way.
Just iterate over each line in the file. Python automatically checks for the End of file and closes the file for you (using the with
syntax).
with open('fileName', 'r') as f:
for line in f:
if 'str' in line:
break
There are situations where you can't use the (quite convincing) with... for...
structure. In that case, do the following:
line = self.fo.readline()
if len(line) != 0:
if 'str' in line:
break
This will work because the the readline()
leaves a trailing newline character, where as EOF is just an empty string.
You can stop the 2-line separation in the output by using
with open('t.ini') as f:
for line in f:
print line.strip()
if 'str' in line:
break
The simplest way to read a file one line at a time is this:
for line in open('fileName'):
if 'str' in line:
break
No need for a with-statement or explicit close. Notice no variable 'f' that refers to the file. In this case python assigns the result of the open() to a hidden, temporary variable. When the for loop ends (no matter how -- end-of-file, break or exception), the temporary variable goes out of scope and is deleted; its destructor will then close the file.
This works as long as you don't need to explicitly access the file in the loop, ie, no need for seek, flush, or similar. Should also note that this relies on python using a reference counting garbage collector, which deletes an object as soon as its reference count goes to zero.
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