Get only second last record - mysql-query

Question

I have a table record like below:-

my_table

        id |      rating | description

         1 |         0.0 | bed
         2 |         1.0 | good
         3 |         0.0 | bed
         4 |         1.0 | good
         5 |         0.0 | bed
         6 |         0.0 | bed
         7 |         0.0 | bed

Now I shorted this table by rating and I got following result. (Query : SELECT * FROM my_table ORDER BY rating DESC)

Result table

        id | rating      | description

         2 |         1.0 | good
         4 |         1.0 | good
         1 |         0.0 | bed
     ==> 3 |         0.0 | bed
         5 |         0.0 | bed
         6 |         0.0 | bed
         7 |         0.0 | bed

Now I want previous record of id = 3.

expected result

        id | rating      | description

         1 |         0.0 | bed

How can I achieve it. within single mysql query? Please help me.

Answer 1

用这个：

SELECT * FROM my_table ORDER BY rating DESC LIMIT 2,1

Answer 2

Try this

SELECT prev.id, rating, description
FROM my_table current
JOIN my_table prev
  ON (prev.rating < current.rating) 
     OR (prev.rating = current.rating 
        AND (prev.description < current.description 
            OR (prev.description = current.description AND prev.id < current.id)))
WHERE current.id = @currentId
ORDER BY prev.rating desc, prev.description desc, prev.id desc
LIMIT 1

Answer 3

Try this for a quick solution:

SELECT * FROM my_table WHERE rating='0.0' and id<'3' ORDER BY id DESC LIMIT 1

This will select the row with the next lowest ID than the one specified that has a rating of 0.0. This will work without sorting BUT will not retrieve any rows that have a rating of 1.0, even if they would be the next line.

Answer 4

try this:

select * from my_table 
where rating<(select max(rating) from my_table)
and
id<3
limit 1;