mysql-query other table condition PHP

Question

I have this table in mysql called safespot

+---------+---------------+
| term_id | userid | safe |
+---------+--------|------+
|       1 | 1      |  large number, unix timestamp here
|       1 | 2      | large number, unix timestamp here
|       1 | 3      | large number, unix timestamp here
|       1 | 4      | large number, unix timestamp here
+---------+--------+

And this is table users :

+----+-------------+-------------+
| id |    userid   |    cash     |
+----+-------------+-------------+
|  1 |     1       |    100000   |
|  2 |     2       |    100000   |
|  3 |     3       |    100000   |
+----+-------------+-------------+

how can i do something like

SELECT * FROM `users` where `userid`=1 and `cash`>= 1000 and " userid do not exist in table safespot" or "if the user exists in the safestop table, check if the current timestamp is higher than the safe colum)

So basically do a query that also would return it if userid dont exist in safespot table, or if it does, that timestamp is higher than safe_value.

Answer 1

SELECT * FROM `users` WHERE `userid`=1 AND `cash`>= 1000 AND (userid NOT IN (
        SELECT DISTINCT userid FROM safespot
    ) OR (userid IN (
        SELECT DISTINCT userid FROM safespot WHERE safe < UNIX_TIMESTAMP()
    )
)

Answer 2

Use WHERE NOT EXISTS like

SELECT u.* FROM `users` u
where u.`userid`=1 
and u.`cash` >= 1000 
and ( NOT EXISTS ( select 1 from safespot where userid <> u.userid)
or EXISTS (select 1 from safestop where userid = u.userid and safe < CURRENT_TIMESTAMP));

Answer 3

SELECT * FROM users u
LEFT JOIN safespot s ON s.userid = u.userid 
WHERE
    u.userid = 1
    AND u.cash = 1000
    AND (s.userid IS NULL OR s.safe > UNIX_TIMESTAMP())

This returns users where

• there is no entry in safespot for the given userid, or
• there is an entry in safespot with the value of safe greater than the current timestamp.