Convert number to month name in PHP

Question

I have this PHP code:

$monthNum = sprintf("%02s", $result["month"]);
$monthName = date("F", strtotime($monthNum));

echo $monthName;

But it's returning December rather than August .

$result["month"] is equal to 8, so the sprintf function is adding a 0 to make it 08 .

Answer 1

The recommended way to do this:

Nowadays, you should really be using DateTime objects for any date/time math. This requires you to have a PHP version >= 5.2. As shown in Glavić's answer , you can use the following:

$monthNum  = 3;
$dateObj   = DateTime::createFromFormat('!m', $monthNum);
$monthName = $dateObj->format('F'); // March

The ! formatting character is used to reset everything to the Unix epoch . The m format character is the numeric representation of a month, with leading zeroes.

Alternative solution:

If you're using an older PHP version and can't upgrade at the moment, you could this solution. The second parameter of date() function accepts a timestamp, and you could use mktime() to create one, like so:

$monthNum  = 3;
$monthName = date('F', mktime(0, 0, 0, $monthNum, 10)); // March

If you want the 3-letter month name like Mar , change F to M . The list of all available formatting options can be found in the PHP manual documentation .

Answer 2

Just because everyone is using strtotime() and date() functions, I will show DateTime example:

$dt = DateTime::createFromFormat('!m', $result['month']);
echo $dt->format('F');

Answer 3

Use mktime() :

<?php
 $monthNum = 5;
 $monthName = date("F", mktime(0, 0, 0, $monthNum, 10));
 echo $monthName; // Output: May
?>

See the PHP manual : http://php.net/mktime

Answer 4

To do the conversion in respect of the current locale, you can use the strftime function:

setlocale(LC_TIME, 'fr_FR.UTF-8');                                              
$monthName = strftime('%B', mktime(0, 0, 0, $monthNumber));

date doesn't respect the locale, strftime does.

Answer 5

strtotime expects a standard date format, and passes back a timestamp.

You seem to be passing strtotime a single digit to output a date format from.

You should be using mktime which takes the date elements as parameters.

Your full code:

$monthNum = sprintf("%02s", $result["month"]);
$monthName = date("F", mktime(null, null, null, $monthNum));

echo $monthName;

However, the mktime function does not require a leading zero to the month number, so the first line is completely unnecessary, and $result["month"] can be passed straight into the function.

This can then all be combined into a single line, echoing the date inline.

Your refactored code:

echo date("F", mktime(null, null, null, $result["month"], 1));

...

Answer 6

There are many ways to print a month from the given number. Pick one suite for you.

1. date() function along with parameter 'F'

Code example:

$month_num = 10;
echo date("F", mktime(0, 0, 0, $month_num, 10)); //output: October

2. By creating php date object using createFromFormat()

Code Example

$dateObj   = DateTime::createFromFormat('!m', $monthNum);
echo "month name: ".$dateObj->format('F'); // Output: October

3. strtotime() function

echo date("F", strtotime('00-'.$monthNum.'-01')); // Output: October

4. mktime() function

echo date("F", mktime(null, null, null, $monthNum)); // Output: October

5. By using jdmonthname()

$jd=gregoriantojd($monthNum,10,2019);
echo jdmonthname($jd,0); // Output: Oct

Answer 7

If you just want an array of month names from the beginning of the year to the end eg to populate a drop-down select, I would just use the following;

for ($i = 0; $i < 12; ++$i) {
  $months[$m] = $m = date("F", strtotime("January +$i months"));
}

Answer 8

If you have the month number, you can first create a date from it with a default date of 1st and default year of the current year, then extract the month name from the date created:

echo date("F", strtotime(date("Y") ."-". $i ."-01"))

This code assumes you have your month number stored in $i

Answer 9

$monthNum = 5;
$monthName = date("F", mktime(0, 0, 0, $monthNum, 10));

I found this on https://css-tricks.com/snippets/php/change-month-number-to-month-name/ and it worked perfectly.

Answer 10

adapt as required

$m='08';
$months = array (1=>'Jan',2=>'Feb',3=>'Mar',4=>'Apr',5=>'May',6=>'Jun',7=>'Jul',8=>'Aug',9=>'Sep',10=>'Oct',11=>'Nov',12=>'Dec');
echo $months[(int)$m];

Answer 11

You need set fields with strtotime or mktime

echo date("F", strtotime('00-'.$result["month"].'-01'));

With mktime set only month. Try this one:

echo date("F", mktime(0, 0, 0, $result["month"], 1));

Answer 12

this is trivially easy, why are so many people making such bad suggestions? @Bora was the closest, but this is the most robust

/***
 * returns the month in words for a given month number
 */
date("F", strtotime(date("Y")."-".$month."-01"));

this is the way to do it

Answer 13

Am currently using the solution below to tackle the same issue:

//set locale, 
setlocale(LC_ALL,"US");

//set the date to be converted
$date = '2016-08-07';

//convert date to month name
$month_name =  ucfirst(strftime("%B", strtotime($date)));

echo $month_name;

To read more about set locale go to http://php.net/manual/en/function.setlocale.php

To learn more about strftime go to http://php.net/manual/en/function.strftime.php

Ucfirst() is used to capitalize the first letter in a string.

Answer 14

This for all needs of date-time converting

 <?php
 $newDate = new DateTime('2019-03-27 03:41:41');
 echo $newDate->format('M d, Y, h:i:s a');
 ?>

Answer 15

您只需一行即可完成：

DateTime::createFromFormat('!m', $salary->month)->format('F'); //April

Answer 16

date("F", strtotime($result["month"]))

使用上面的代码

Answer 17

<?php
$month =1;
$convert =DateTime::createFromFormat('!m', $month);
echo $convert->format('F');
?>

Answer 18

$days = ['', 'Jan', 'Feb', 'Mar', 'Apr', 'Mai', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec'];
$month = ( date('m') < 10 ) ? date('m')[1] : date('m');

That extracts the months.

Answer 19

I think using cal_info() is the easiest way to convert from number to string.

$monthNum = sprintf("%02s", $result["month"]); //Returns `08`
$monthName = cal_info(0); //Returns Gregorian (Western) calendar array
$monthName = $monthName[months][$monthNum];

echo $monthName; //Returns "August"

See the docs for cal_info()

Answer 20

To get month name by providing month number

$month_number = 5;

$monthName = date('F', mktime(0, 0, 0, $month_number, 10));

Where 'F' will return you month name Eg. 'May'

Answer 21

This is how I did it

// sets Asia/Calcutta time zone
date_default_timezone_set("Asia/Calcutta");

//fetches current date and time
$date = date("Y-m-d H:i:s");

$dateArray = date_parse_from_format('Y/m/d', $date);
$month = DateTime::createFromFormat('!m', $dateArray['month'])->format('F');
$dateString = $dateArray['day'] . " " . $month  . " " . $dateArray['year'];

echo $dateString;

returns 30 June 2019

Answer 22

A simple tricks here you can use strtotime() function workable as per your need, a convert number to month name.

1.If you want a result in Jan, Feb and Mar Then try below one with the 'M' as a parameter inside the date.

$month=5;
$nmonth = date('M',strtotime("01-".$month."-".date("Y")));
echo $nmonth;

Output : May

/2. You can try with the 'F' instead of 'M' to get the full month name as an output January February March etc.

$month=1;
$nmonth = date('M',strtotime("01-".$month."-".date("Y")));
echo $nmonth;

Output : January

Answer 23

This respect the LC_TIME

$date = new DateTime('2022-04-05');
$mes = strftime('%B', $date->getTimestamp());

Answer 24

My approach

$month = date('m');
$months_of_year = array(
    array('month' => '01', 'translation' => 'janeiro'),
    array('month' => '02', 'translation' => 'fevereiro'),
    array('month' => '03', 'translation' => 'março'),
    array('month' => '04', 'translation' => 'abril'),
    array('month' => '05', 'translation' => 'maio'),
    array('month' => '06', 'translation' => 'junho'),
    array('month' => '07', 'translation' => 'julho'),
    array('month' => '08', 'translation' => 'agosto'),
    array('month' => '09', 'translation' => 'setembro'),
    array('month' => '10', 'translation' => 'outubro'),
    array('month' => '11', 'translation' => 'novembro'),
    array('month' => '12', 'translation' => 'dezembro'),
);
$current_month = '';
foreach ($months_of_year as $key => $value) 
{
    if ($value['month'] == $month){
        $current_month = $value['translation'];  
        break;  
    }
}
echo("mes:" . $current_month);

Answer 25

利用：

$name = jdmonthname(gregoriantojd($monthNumber, 1, 1), CAL_MONTH_GREGORIAN_LONG);

Answer 26

You can just use monthname() function in SQL.

SELECT monthname(date_column) from table group by monthname(date_column)

Answer 27

对于php 7.1

 $monthyear= date("M Y");

Answer 28

使用本地函数，例如jdmonthname() ：

echo jdmonthname($monthNum, CAL_MONTH_GREGORIAN_LONG);

Answer 29

I figured everyone looking for this answer was probably just trying to avoid writing out the whole if/else statements, so I wrote it out for you so you can copy/paste. The only caveat with this function is that it goes on the actual number of the month, not a 0-indexed number, so January = 1, not 0.

function getMonthString($m){
    if($m==1){
        return "January";
    }else if($m==2){
        return "February";
    }else if($m==3){
        return "March";
    }else if($m==4){
        return "April";
    }else if($m==5){
        return "May";
    }else if($m==6){
        return "June";
    }else if($m==7){
        return "July";
    }else if($m==8){
        return "August";
    }else if($m==9){
        return "September";
    }else if($m==10){
        return "October";
    }else if($m==11){
        return "November";
    }else if($m==12){
        return "December";
    }
}