Difference between result of character and integer pointer

Question

I was trying to execute the following code:

#include <iostream>
using namespace std;

int main()
{
    int arr[4] = {1,2,3,4};
    int *p;
    p = arr;
    cout << "p=" << p << endl;

    char ch3[4] = {'c','d','e'};
    char *ptr;
    ptr = ch3;
    cout << ptr << endl;
    getchar();
    return 0;
}

When I print the pointer p, it prints the address of the array 'arr' which is stored in it, whereas when I print the pointer ptr, it prints the array ch3 and not the address of it. I wanted to know why is this happening.

Answer 1

Because operator<< is overloaded for const char* - that overload prints the char array located at that address.

To see the address itself, you'll need to cast it to void* :

cout<<static_cast<void*>(ptr)<<endl;