I'm trying to use Java for the first time on my Mac (OS X 10.6.8). A simple "Hello World" example works fine. However, now I'm trying to input data via command prompts and compilation fails on syntax, expecting a semicolon. Code comes from the book: "Java Programming: From Problem Analysis to Program Design", 5th Edition, by DS Malik.
The compilation error is:
javac Example2_17.java
Example2_17.java:18: ';' expected
firstName console.next();
^
1 error
The java version is:
java -version
java version "1.6.0_51"
Java(TM) SE Runtime Environment (build 1.6.0_51-b11-457-10M4509)
Java HotSpot(TM) 64-Bit Server VM (build 20.51-b01-457, mixed mode)
The java code is:
import java.util.*;
public class Example2_17
{
static Scanner console = new Scanner(System.in);
public static void main(String[] args)
{
String firstName;
String lastName;
int age;
double weight;
System.out.println("Enter first name, last name, age, and weight separated by spaces.");
firstName console.next(); // <----------- ERROR HERE!
//lastName console.next();
//age console.nextIng();
//weight console.nextDouble();
//System.out.println("Name: " + firstName + " " + lastName);
//System.out.println("Age: " + age);
//System.out.println("Weight: " + weight);
}
}
Any help is greatly appreciated.
Thanks!
You're missing an assignment operator =
firstName = console.next();
Without the operator the compiler considers the statement a declaration so complains when it doesn't find ;
at the expected location.
You appear to be missing an equal sign after firstName.
Is..
firstName console.next();
Should be...
firstName = console.next();
You have to use try and catch statements.There must be an exception or use throwIOException. There is another error /age console.nextIng(); you added an Ing intstead of int and that may be another cause of your error.You have also forgotten the "=" operater to store the data extracted into your local variable.`
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