the code below display the row 116 twice, it won't display row 118. Any idea how to solve this issue?
$data = mysql_query("SELECT * FROM item WHERE dcid IN('116','118')")
or die(mysql_error());
$info = mysql_fetch_array($data);
foreach ($info as $item) {
echo($item);
}
mysql_fetch_array only fetches a single row. Typically it is used in a while loop to cycle through all the results.
To continue your example above:
$data = mysql_query("SELECT * FROM item WHERE dcid IN('116','118')") or die(mysql_error());
while ($item = mysql_fetch_array($data)) {
echo($item)
}
your query must be as:
$data = mysql_query("SELECT * FROM item WHERE dcid IN('116','118')") or die(mysql_error());
while ($item = mysql_fetch_array($data)) {
echo $item['column_name1'];
} echo $item['column_name2'];
mysql_fetch_array returns a single row in an array like this that contains both an associative array and a regular numeric-keyed result set of your row.
0=> column,
column=>column
Thats why it returns twice in foreach.Use it like this
mysql_fetch_array($result, MYSQL_ASSOC);
Also, if dcid is your key and it's autoincrementing ( ID for rows ) you can also use LIMIT 116,118.
For more info: http://php.about.com/od/mysqlcommands/g/Limit_sql.htm
use group by
as this
$data =mysql_query("SELECT * FROM item WHERE dcid IN('116','118') group by dcid")
or die(mysql_error());
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