I have a problem with my code.Please help me to solve it. Program should quit and return average when q is entered. If you enter 5 numbers it is working fine. The array size should be 20. Here is the code:
import java.util.Scanner;
public class test{
public static void main(String[] args){
int x;
int count=0;
char q= 'q';
Scanner input = new Scanner(System.in);
int[] array = new int[5];
System.out.print("You have entered 0 numbers, please enter a number or q to quit:" );
while (input.hasNextInt()){
for (int i = 0; i < array.length; i++)
{
array[i] = input.next();
count++;
System.out.print("You have entered " +count+ " numbers, please enter a number or q to quit:" );
}
}
System.out.println("Average is " + Average(array));
}
public static int Average(int[] array) {
int sum = 0;
for (int i = 0; i < array.length; i++)
sum += array[i];
return sum / array.length;
}
}
Use List instead of array. Check if input is q print the average and return system.exit(0)
您应该在每个 input.nextInt() 之前检查 input.hasNextInt()。
You're using a compound loop which is negating the ability to break out of the first/outter loop.
You should consolidate the two loops into a single loop, looking for two escape conditions, either the user presses q
or they enter 5 numbers...
Because you're expecting mixed input, you need to convert the input manually to an int....
String line = null;
// Loop until count >= 5 or the user inputs "q"
while (count < array.length && !(line = input.nextLine()).equalsIgnoreCase("q")) {
try {
// Convert the input to an int...
int value = Integer.parseInt(line);
array[count] = value;
count++;
System.out.print("You have entered " + count + " array, please enter a number or q to quit:");
} catch (NumberFormatException exp) {
System.out.println(line + " is not an int value...");
}
}
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.