regular expression for given file path

Question

This is the most recent segment of regexp i tried....but every time it is giving -1,I want it to match with my string str....I have started with basic file path,it should return any value greater than -1 if matched.

var str=" c:\folder1\ ";
var n;
var y=/^[a-z]\:\\(folder1)?\\$/g;
n=str.search(y);
alert(n);

I want to write it for specific folder names...it should accept both the string given below... example

File C:\\Program Files (x86)\\Webdeveloper\\dfg.dll

File C:\\Program Files\\Webdeveloper\\dfg.exe

file names will exist with some dll or exe extensions.

/[c]{1}[:]{1}\\{1}(folder1){1}\\/ shows match for folder1 when i am using http://regex101.com/#javascript,I am passing the string "file c:\\folder1\\ is corrupted" . but it is not working for whole path string.

Thanks in advance!

Answer 1

You have trailing whitespaces in your source string, so your regexp won't match. Additionally, you should add slashes to your source string to make it capturable. change your code to:

var str=" c:\\folder1\\ ";
var n;
var y=/^\s*[a-z]\:\\(folder1)?\\\s*$/g;
str.match(y) // [" c:\folder1\ "]

\\f is a escape character which means formfeed.

Answer 2

Use this regular expression

^[C][:]\\[A-Z+a-z ()0-9\\]+[.][a-z]+$

Demo/Testing

Answer 3

Try this:

here in every '\\\\',one \\ is escape character and other \\ is litral.

var str="c:\folder1\abc.txt";
var n;
var y=/^(c:\\folder1\\abc\.txt)$/;
n=str.search(y);
alert(n);