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MySQL Convert String To Date Calculate Age And Order BY Age

 原文  2013-09-25 16:27:59  2   1    mysql/ sql

Question

I'm trying to write a mysql query that will convert a string to a date and then calculate an age and then count the ages and group by age.

I have the string to date and calculate age query: 

SELECT YEAR(CURRENT_TIMESTAMP) - YEAR(STR_TO_DATE( birthday,  '%m/%d/%Y' )) - (RIGHT(CURRENT_TIMESTAMP, 5) < RIGHT(STR_TO_DATE( birthday,  '%m/%d/%Y' ), 5)) as age 
  FROM `persons`

But I can't count and group by age. Could anyone help me?

1 answers

solution1
 1 ACCPTED  2013-09-25 16:32:10

SELECT  EXTRACT(YEAR FROM (FROM_DAYS(DATEDIFF(NOW(),STR_TO_DATE(birthday, '%m/%d/%Y'))))) + 0 age,
        COUNT(*) TotalCount
FROM    tableNAme
GROUP   BY EXTRACT(YEAR FROM (FROM_DAYS(DATEDIFF(NOW(),STR_TO_DATE(birthday, '%m/%d/%Y'))))) + 0
ORDER   BY TotalCount DESC

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