Why does println not show up - Java

Question

I am a newb with Java so don't bite me please.. I've made this method, but it will not show up in the console screen, why?

public class ADSopgave2K1 {

public static void main(String[] args) {

        }

        public void print(String s, int pos) {
            s = "";
            pos = s.length();
            int count = s.length();
            char[] ray;

            System.out.println("Enter a word: ");
            Scanner userInputF = new Scanner(System.in);
            s = userInputF.nextLine();

            ray = s.toCharArray();

            for (int t = 0; t < s.length(); t++) {
                System.out.println(ray[t]);
                return;
            }
        }
    }

Answer 1

You did not call that method yet. Try to call your method.

public static void main(String[] args) {
ADSopgave2K1  intance=new ADSopgave2K1();
intance.print();
        }

Edit

 public void print() {

    System.out.println("Enter a word: ");
    Scanner userInputF = new Scanner(System.in);
    String s = userInputF.nextLine();

    char[]  ray = s.toCharArray();

    for (int t = 0; t < s.length(); t++) {
        System.out.println(ray[t]);
    }
}

Answer 2

When you run your program, Java will call main(String[] args) .

But this is an empty function, so you will not see any output.

Answer 3

Becasue, you did not call anything in main(String[] args) method. Make your print method static and call this to your main method.

public static void print(String s, int pos){

}

EDIT:

public static void main(String[] args){
   print("test",1);
}

Answer 4

您必须通过为您的类创建实例来调用main（）中的方法

Answer 5

ADSopgave2K1 r=new ADSopgave2K1();
    r.print("jai", 4);

Create an object of your class in side main method and then call its method.

Answer 6

You should call print() method.

public class ADSopgave2K1 {

    public static void main(String[] args)
    {
        print("Hello World", 1);
    }

    public void print(String s, int pos) 
    {
        s = "";
        pos = s.length();
        int count = s.length();
        char[] ray;

        System.out.println("Enter a word: ");
        Scanner userInputF = new Scanner(System.in);
        s = userInputF.nextLine();

        ray = s.toCharArray();

        for (int t = 0; t < s.length(); t++) {
            System.out.println(ray[t]);
            return;
        }
    }

}

Answer 7

either you make print method static and call it with correct argument Or
make instance of ADSopgave2K1 class and call it with correct args