I want to deserialize xml into c#. But I am getting error and cannot fix it.
Error is:
"There is an error in XML document (1, 2)."
...
"<A xmlns=''> was not expected."
Deserialize code:
public static object XmlDeserializeFromString(string objectData, Type type)
{
var xmlAttributes = new XmlAttributes();
var xmlAttributeOverrides = new XmlAttributeOverrides();
xmlAttributes.Xmlns = false;
xmlAttributeOverrides.Add(typeof(A10), xmlAttributes);
var serializer = new XmlSerializer(type, xmlAttributeOverrides);
object result=null;
try
{
using (TextReader reader = new StringReader(objectData))
{
result = serializer.Deserialize(reader);
}
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
return result;
}
The class is:
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(TypeName = "A-1.0", Namespace = "")]
[System.Xml.Serialization.XmlRootAttribute("A", Namespace = "", IsNullable = false)]
public class A10
{
private string versField;
private string typeField;
[System.Xml.Serialization.XmlAttributeAttribute()]
public string id
{
get
{
return this.idField;
}
set
{
this.idField = value;
}
}
[System.Xml.Serialization.XmlAttributeAttribute()]
public string type
{
get
{
return this.typeField;
}
set
{
this.typeField = value;
}
}
}
And testing by:
string xml = "<A vers=\"1.0\" type=\"pd\">";
A10 a = (A10) XmlDeserializeFromString(xml, typeof(A10));
The exception is thrown on line:
result = serializer.Deserialize(reader);
Why this is happening? How to solve this?
<A vers="1.0" type="pd">
is not XML. See the specs . Your root element is missing its closing tag.
Make your document look like this:
<A vers="1.0" type="pd"></A>
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