I tried something I did in Javascript. But it says http://play.golang.org/p/qlWLI03Dnl
package main
import "fmt"
import "regexp"
import "strings"
func swapit(str string) string {
var validID = regexp.MustCompile(`[a-z]|[A-Z]`)
return validID.ReplaceAllString(str, func(${0}, ${1}, ${2}) string {
return (${1}) ? strings.ToUpper(${0}) : strings.ToLower(${0})
})
}
func main() {
fmt.Println(swapit("hello wOrld."))
// HELLO WoRLD.
}
I also tried this removing ? : syntax but still does not work. http://play.golang.org/p/mD6_78zzo1
Does really go not support this? Do I just give up and just bruteforce each character to change cases?
Thanks a lot
As @James Henstridge already pointed out, there are multiple problems with your code. This answer will not focus on the errors, but rather a different way of solving the problem.
If your aim is to learn about using regexp in Go, this answer of mine is useless.
If your aim is to get learn how to make a function that swaps cases, then I suggest a solution without regexp, utilizing the unicode
package instead:
package main
import (
"bytes"
"fmt"
"unicode"
)
func SwapCase(str string) string {
b := new(bytes.Buffer)
for _, r := range str {
if unicode.IsUpper(r) {
b.WriteRune(unicode.ToLower(r))
} else {
b.WriteRune(unicode.ToUpper(r))
}
}
return b.String()
}
func main() {
fmt.Println(SwapCase("Hej värLDen."))
}
Output:
hEJ VÄRldEN.
This solution will handle all non AZ characters as well, such as ö-Ö and å-Å.
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