find all lines in a file with number range

Question

I have text as below in a file.

abcdxyz Time(0.010),blah blah blah
abcdxyz Time(1.010),blah blah blah
abcdxyz Time(0.010),blah blah blah
abcdxyz Time(2.010),blah blah blah
abcdxyz Time(3.010),blah blah blah
abcdxyz Time(8.010),blah blah blah

I want to grep all lines where value in Time() is greater than 2.00 . How can I do this in ksh.

FYI: my OS is Red hat linux and I am using ksh

Answer 1

Try using awk

awk -F'[()]' '$2>2{print}' file

Output:

abcdxyz Time(2.010),blah blah blah
abcdxyz Time(3.010),blah blah blah
abcdxyz Time(8.010),blah blah blah

Answer 2

这有效（在AIX / ksh上）

sed 's/\(.*\)Time(\(.*\))\(.*\)/\2 \1Time(\2)\3/' a.dat | awk '{ if ($1 > 2.0) { $1="" ;  print } }'