How to delete the pattern between start of the pattern and a line before the end pattern using sed or perl command?

Question

Here is the input file

{1:IRVTUS30XXX}{2:I304dfaffaefa}{3:fewfa]}
:15A:
:20:1234556
:22:dsafas
dsafafaf
erwfafgr
:23:fewfd
:24:firh
:60:uncenjnjcdv
:72:uenuernfk
12345
-}

Here i want to delete some tags information from the input file. (Tags are :15A: :22: which are in between colon are called tags)

If i want to delete tag 20 i can use the below perl command:

perl -i -pe 's/:20:(.*)\r\n//g' file

But for the tags like :22: or :72: its mulitiple line tags.. How can i delete those?

Answer 1

Here you have the expression to select both tag no. 22 and tag no. 72 :

:(72|22):([\w\d]*(\r?\n|\r\n?)+)+

Here 'sa test of match.

Answer 2

Sample code for removing tag 22 (works with multi-lines or single line):

% perl -00 -pe 's/^:22:.*?(?=(?:^:\d+\w*|$))//ms' file.txt
{1:IRVTUS30XXX}{2:I304dfaffaefa}{3:fewfa]}
:15A:
:20:1234556
:23:fewfd
:24:firh
:60:uncenjnjcdv
:72:uenuernfk
12345
-}