how to get the associated unique ID of the recently added entry in MYSQL
Question
i need some workaround/solutions for my ajax issue
i have this simple <html>
<textarea class="msg"></textarea>
<button type="button" class="submit">Submit</button>
<div class="messages">
<?php some php while loop here to display all submitted messages?>
</div>
when i click submit, this ajax gets the value of <textarea> and submits the data into messages.php
$(function() {
$(document).on('click','.submit', function () {
var msg = $('.msg').val();
$.ajax({
type:"POST",
url:"messages.php",
data: "msg=" + msg,
success: function(html) {
$(html).prependTo('.messages');
}
});
});
});
this is my messages.php
//insert into database
$msg= $_POST['msg'];
$db = dbConnect();
$insert= "INSERT INTO messages (content)values ('$msg')";
$db->query($insert);
//get the recently added message and echo it
$query = //select the ID of the added message
$result = $db->($query);
$row = $result->fetch_assoc());
echo $row['id'];
echo $row['content'];
the part where im struggling, is how to query the message being submitted right after it was inserted to the database, so i could echo it in php, and fetch it via ajax.
success: function(html) {
$(html).prependTo('.messages');
}
i know i need some unique identifier of the submitted message, but im not sure how to code it properly.
edit:
ok, the reason i needed to query the added entry, is to get the associated ID of that entry, because i will be using the ID for other functions. all i really need is a reference on my submitted data
2 answers
solution1
2 ACCPTED 2013-10-17 16:15:11
$id = $db->insert_id;
$query = "SELECT * FROM messages WHERE id = $id";
$result = $db->query($query);
$row = $result->fetch_assoc();
echo $row['id'];
echo $row['content'];
solution2
-1 2013-10-17 16:14:25
use last inserted id function it can also help if you are inserting in two different table and inputing same row values
//insert query in this line
$lastid=mysqli_insert_id()//php function
$que = mysqli_query("SELECT * FROM table where id= '$lastid' ");
$r = mysql_fetch_array($que);
echo $r['id'];
hopes this help
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