I have some simple code that does the job but gives an uncaught error.
ck.setMode('source');
ck.setMode( 'wysiwyg');
This is giving me the message:
Uncaught TypeError: Cannot read property 'on' of undefined
I know it's probably a bad practice but the error does not cause any problems and I would like to avoid it showing in the browser. Is there some way that I could enclose this code so it does not give a browser console alert?
Here's the code that encloses the above:
ngModel.$render = function () {
if (typeof ngModel.$modelValue != 'undefined') {
if (ngModel.$modelValue != null) {
ck.setData(ngModel.$modelValue);
timer = setTimeout(function () {
ck.setData(ngModel.$modelValue);
}, 1000);
timer = setTimeout(function () {
ck.setMode('source');
ck.setMode('wysiwyg');
}, 1000);
}
}
};
You may use code like this:
window.onerror = function(message, url, lineNumber) {
// maybe some handling?
return true; // prevents browser error messages
};
It prevents all error messages, so use it with care.
You can put your code block inside a try catch. So your code would become like this.
try {
ck.setMode('source');
ck.setMode( 'wysiwyg');
}
catch (error) {
// handle your error
}
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