I am using the following code to find a string in an std::vector
of string
type. But how to return the position of particular element?
Code:
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int main() {
vector<string> vec;
vector<string>::iterator it;
vec.push_back("H");
vec.push_back("i");
vec.push_back("g");
vec.push_back("h");
vec.push_back("l");
vec.push_back("a");
vec.push_back("n");
vec.push_back("d");
vec.push_back("e");
vec.push_back("r");
it=find(vec.begin(),vec.end(),"r");
//it++;
if(it!=vec.end()){
cout<<"FOUND AT : "<<*it<<endl;
}
else{
cout<<"NOT FOUND"<<endl;
}
return 0;
}
Output:
FOUND AT : r
Expected Output:
FOUND AT : 9
You can use std::distance
for that:
auto pos = std::distance(vec.begin(), it);
For an std::vector::iterator
, you can also use arithmetic:
auto pos = it - vec.begin();
Use following :
if(it != vec.end())
std::cout<< "Found At :" << (it-vec.begin()) ;
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int main() {
vector<string> vec;
vector<string>::iterator it;
vec.push_back("H");
vec.push_back("i");
vec.push_back("g");
vec.push_back("h");
vec.push_back("l");
vec.push_back("a");
vec.push_back("n");
vec.push_back("d");
vec.push_back("e");
vec.push_back("r");
it=find(vec.begin(),vec.end(),"a");
//it++;
int pos = distance(vec.begin(), it);
if(it!=vec.end()){
cout<<"FOUND "<< *it<<" at position: "<<pos<<endl;
}
else{
cout<<"NOT FOUND"<<endl;
}
return 0;
使用此声明:
it = find(vec.begin(), vec.end(), "r") - vec.begin();
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