I want to know if exist some way to select the table bellow...
ID | DOCNo | Date
1 | 20 | 12-DEC-12
2 | 21 | 02-NOV-12
3 | 20 | 18-JAN-13
4 | 20 | 10-APR-13
5 | 22 | 12-DEC-12
to do something like this in SQL SERVER 2008:
DOCNo | ID1 | Date1 | ID2 | Date2 | ID3 | Date3
20 | 1 | 12-DEC-12 | 3 | 18-JAN-13 | 4 | 10-APR-13
21 | 2 | 02-NOV-12 | NULL | NULL | NULL | NULL
22 | 5 | 12-DEC-12 | NULL | NULL | NULL | NULL
*The DOCNo will never have more than 3 records in table
I am using SQL Server 2008.
Thanks!!!
MS SQL Server 2008 Schema Setup :
CREATE TABLE Table1
([ID] int, [DOCNo] int, [Date] varchar(9))
;
INSERT INTO Table1
([ID], [DOCNo], [Date])
VALUES
(1, 20, '12-DEC-12'),
(2, 21, '02-NOV-12'),
(3, 20, '18-JAN-13'),
(4, 20, '10-APR-13'),
(5, 22, '12-DEC-12'),
(6, 23, '21-JAN-13'),
(7, 23, '24-FEB-13')
;
Query 1 :
SELECT r1.DOCNo,
r1.ID as ID1, r1.Date as Date1,
r2.ID as ID2, r2.Date as Date2,
r3.ID as ID3, r3.Date as Date3
FROM Table1 r1
LEFT OUTER JOIN Table1 r2 ON r1.DOCNo = r2.DOCNo AND r1.ID < r2.ID
LEFT OUTER JOIN Table1 r3 ON r1.DOCNo = r3.DOCNo AND r1.ID < r3.ID
AND r2.ID < r3.ID
WHERE r1.ID = (SELECT min(ID)
FROM Table1
WHERE DOCNo = r1.DOCNo
GROUP BY DOCNo)
AND (CASE WHEN (SELECT count(*)
FROM Table1
WHERE DOCNo = r1.DOCNo
GROUP BY DOCNo) = 2 THEN r2.ID
WHEN (SELECT count(*)
FROM Table1
WHERE DOCNo = r1.DOCNo
GROUP BY DOCNo) = 3 THEN r3.ID ELSE 1 END) IS NOT NULL
Results :
| DOCNO | ID1 | DATE1 | ID2 | DATE2 | ID3 | DATE3 |
|-------|-----|-----------|--------|-----------|--------|-----------|
| 20 | 1 | 12-DEC-12 | 3 | 18-JAN-13 | 4 | 10-APR-13 |
| 21 | 2 | 02-NOV-12 | (null) | (null) | (null) | (null) |
| 22 | 5 | 12-DEC-12 | (null) | (null) | (null) | (null) |
| 23 | 6 | 21-JAN-13 | 7 | 24-FEB-13 | (null) | (null) |
An easy way to get the final result would be to use row_number()
to generate a sequence for each docno
and then apply an aggregate function with a CASE expression:
select docno,
max(case when seq = 1 then id end) id1,
max(case when seq = 1 then date end) date1,
max(case when seq = 2 then id end) id2,
max(case when seq = 2 then date end) date2,
max(case when seq = 3 then id end) id3,
max(case when seq = 3 then date end) date3
from
(
select id, docno, date,
row_number() over(partition by docno order by date) seq
from yourtable
) d
group by docno;
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