I have a vector of chars and I want to copy the elements in a string vector.I want each cell of the second vector to have k elements of the first, forming a string. Although I have no compiling errors the programm crashes when it forms the string vector.
Thanks in advance!
vector<string> v2;
for(int i = 0; i <= v1.size(); i++){ //v1 is the char vector
for(int j = 0; j <= k; j++){
v2[i] = v2[i] + v1[j];
}
cout << v2[i] << endl;
}
Your vector v2
is empty when you access v2[i]
: this operation is, thus, illegal. You probably want something like
std::vector<std::string> v2;
v2.reserve(v1.size()); // optionally reserve enough elements; may improve performance
for (std::string::const_iterator it(v1.begin()), end(v1.end()); it != end; ++it) {
v2.push_back(std::string(it, it + std::min(k, std::distance(it, end))));
std::cout << v2.back() << '\n';
}
You had to make sure that your other vector has enough elements in it.
(UPDATE: using postfix operation for v2 will save memory and running time, because in that case no temporary variable has to be allocated to perform the addition operation.)
vector <string> v2(v1.size());
for(int i=0;i<=v1.size();i++){ //v1 is the char vector
for (int j=0;j<=k;j++){
v2[i]+=v1[j];
}
cout<<v2[i]<<endl;
}
There's a string constructor that takes a pair of iterators -- use it to grab k
consecutive characters. Then, start the next string where the last one ended (I think this is what your question meant?)
vector<string> v2;
auto p1 = v1.begin();
auto const pend = v1.end();
if (v1.size() > k) {
auto const pendk = pend - k;
do {
auto const p2 = p1 + k; // locate k characters
v2.emplace_back(p1, p2);// make a string from those characters
p1 = p2; // the end of this one is the start of the next
} while (p1 < pendk);
}
if (p1 != pend) // deal with any leftover (<= k) characters at the end
v2.emplace_back(p1, pend);
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