Pass variable to AWK command

Question

I have a AWK command and i want to use it in bash script. I want to give to AWK a big text file as variable.

I have tried:

1. cat $var | awk 'regex'
2. echo $var | awk 'regex'
3. awk 'regex' <<< $var

All three form does not work. When i try these command in shell awk 'regex' file it works. How can i pass a variable as Input to AWK command,i dont want to pass file to AWK . Is that possible or not.

Answer 1

您需要用引号引起来，以防止换行符转换为空格：

echo "$var" | awk 'regex'

Answer 2

Try this :

$ awk -v awkvar="$var" 'BEGIN{if (awkvar ~ "foobar"){print var}}'
foobar

Answer 3

您非常亲密，这也应该有效：

awk 'regex' <<< "$var"