Javascript Regex - contains word AND word from list in any order

Question

I have a requirement to find a specific word AND any words from a list. So far I have this:

^.*?(apple)(?:\W+\w+){0,30}?\W+(ipad|itunes).*

This matches "apple" and either "ipad" or "itunes".

This fails however if "ipad" or "itunes" is before "apple".

Can anyone advise?

Answer 1

You should better use lookahead for that:

/^(?=.*?\bapple\b)(?=.*?\b(ipad|itunes)\b).*$/i

Update: As per this comment from OP: Can you advise how my word limit would fit in here? eg I must find any from the list within 20 words of apple? Can you advise how my word limit would fit in here? eg I must find any from the list within 20 words of apple?

/^(?=.*?\bapple\b)(?=.*?\bapple(\W+\w+){0,20}\b(ipad|itunes)\b).*$/i

Answer 2

Doesn't the simple version work ( http://jsfiddle.net/xhdBQ/1/ ) ?

var list = ["ipad", "itunes"];
var word = "apple";
list.push(word)

var regex = new RegExp("(" + list.join("|") + ")", "g");
console.log(regex);
console.log("blabla...apple,,safsd ssdfipadaad itunes".match(regex))