I want to get ids of some objects. What is the clean way to get them in tuple?
A .values() queryset return this:
MyModel.objects.filter(name__startwith='A').values('id')
>>>> [{'id': 20L}, {'id': 21L}, {'id': 84L}]
And i would like transform/get them into a tuple like:
(20L, 21L, 84L)
The simplest solution is to get values_list
with flat=True
models.MyModel.objects.all().values_list('id', flat=True)
This is similar to values() except that instead of returning dictionaries, it returns tuples when iterated over. Each tuple contains the value from the respective field passed into the values_list() call — so the first item is the first field, etc.
If you only pass in a single field, you can also pass in the flat parameter. If True, this will mean the returned results are single values, rather than one-tuples. An example should make the difference clearer:
What about a generator expression?
tuple(d['id'] for d in MyModel.objects.filter(name__startwith='A').values('id'))
Alternatively:
import operator
tuple(map(lambda x: operator.getitem(x, 'id'), MyModel.objects.filter(name__startwith='A').values('id'))
Or, as an answer that was deleted for some reason suggested, you could do this:
tuple(object.id for object in MyModel.objects.filter(name__startwith='A'))
Alternatively:
import operator
getter = operator.attrgetter('id')
tpl = tuple(map(getter, MyModel.objects.filter(name__startwith='A')))
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