So I've been working on a Password Strength Checker and the way it works is that the user enters some random text into a textfield and then instantaneous visual feedback (breakdown of points) is displayed. I've also added a checkbox, which on being selected, should hide the password ie replace all the chars with asterisks, while preserving the actual text input by the user. A document listener is being used to keep track of changes inside the textfield. (each char on entry gets analyzed and then scored)
So, my question is, how exactly do I mask the user input with asterisks preserving its original value?
Here's what the GUI looks like:
http://speedcap.net/sharing/screen.php?id=files/51/2f/512f9abb3f92a25add7c593e9d80e9e4.png
How exactly do I mask the user input with asterisks preserving its original value?
Use the JPasswordField
which has nice function jPasswordField.getPassword();
to get the password as char[]
to work with.
jPasswordField1.setEchoChar('*')
to mask the password characters with *
.jPasswordField1.setEchoChar((char)0);
Setting a value of 0
indicates that you wish to see the text as it is typed, similar to the behavior of a standard JTextField
.Tutorial and Reference:
使用密码字段而不是使用文本字段
ok thanks for tutorialnya,
and ex,
action chechbox / double click
private void lihatActionPerformed(java.awt.event.ActionEvent evt) {
if (lihat.isSelected()) {
password.setEchoChar((char)0); //password = JPasswordField
} else {
password.setEchoChar('*');
}
}
I solved it as follows:
if ( jPasswordField.getEchoChar() != '\u0000' ) {
jPasswordField.setEchoChar('\u0000');
} else {
jPasswordField.setEchoChar((Character) UIManager.get("PasswordField.echoChar"));
}
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