sql select records having count > 1 where at lease one record has value

Question

I'm trying to get all participants that have more than 1 record in the table where at lease one of those records has IsCurrent = 0 and IsActive = 1

This is what I have so far, but it's not working:

    SELECT  ParticipantId 
    FROM Contact
    WHERE (IsCurrent = 0 AND IsActive = 1 AND ContactTypeId = 1)
    Group by ParticipantId
    Having COUNT(ParticipantId) > 1

This query brings back a record that matches that description, but I need all of the records that match that description, there are more.

Answer 1

You can use EXISTS :

SELECT  ParticipantId 
FROM    Contact
WHERE   EXISTS
        (   SELECT  1
            FROM    Contact c2
            WHERE   c2.ParticipantID = c.ParticipantId
            AND     ContactTypeId = 1
            GROUP BY ParticipantID
            HAVING COUNT(*) > 1
            AND COUNT(CASE WHEN IsCurrent = 0 AND IsActive = 1 THEN 1 END) >= 1
        );

Answer 2

Use it as a subquery and join to it:

select * from 
(
    SELECT  ParticipantId 
    FROM Contact
    WHERE (IsCurrent = 0 AND IsActive = 1 AND ContactTypeId = 1)
    Group by ParticipantId
    Having COUNT(ParticipantId) > 1
) base
inner join Contact c on c.ParticipantId = base.ParticipantID
WHERE (IsCurrent = 0 AND IsActive = 1 AND ContactTypeId = 1)

Answer 3

select 
  ParticipantId
from Contact as c
group by
  ParticipantId
having 
  Count(*) > 1
  and
  Sum(Case when IsCurrent = 0 then 1 else 0 end) >= 1
  and
  Sum(Case when IsActive = 1 then 1 else 0 end) >= 1

I would first try this

Answer 4

I think you should just remove:

AND ContactTypeId = 1

which seems to be an idexed column

Answer 5

  SELECT  ParticipantId 
    FROM Contact
   Group by ParticipantId 
  Having Count(*) > 1 
Intersect
  SELECT  ParticipantId 
    FROM Contact
   WHERE IsCurrent = 0 
     AND IsActive = 1 
     AND ContactTypeId = 1