Generic method invokation with no parameter

Question

If i have a generic method

public <T> ArrayList<T> test(){ return new ArrayList<T>(); }

And invoke him without explicit type parameter then will be returned raw type ArrayList , thus if we invoked generic method without type parameter we are invoked just corresponding non-generic method. Is it true?

Answer 1

No, if you are allowed to invoke the method without an explicit type parameter, that means that the compiler was able to infer the appropriate type for you. That means an ArrayList<WhateverInferredType> will be returned.

Answer 2

No. This method is always called with a type paramater, and the ArrayList will always have a type paramter. The parameter is determined via type inference . In the most basic case (ie just calling the method), the type parameter will be Object .