Here's the code:
<?php
if(isset($_POST['results']) && $_POST['results'] != -1) {
$db = new PDO('mysql:host=localhost;dbname=;charset=utf8', '', '');
echo "<table border='1'>
<tr>
<th>Courses</th>
</tr>";
$stmt = $db->prepare("SELECT title FROM course WHERE `subject_id`=?");
$stmt->execute(array($_POST['results']));
if ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>";
echo "<td>", $row['title'], "</td>";
echo "</tr>";
}
} else {
echo "No results found";
} echo "</table>";
}
?>
This is just returning one result into the table, when there are more results to show.
Where am I going wrong?
remove the if, because it's change the pointer of array(fetch)
if ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { // get the first record, remove this if
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {// get the second record and reset $row
you can change to:
$row = $stmt->fetchAll(PDO::FETCH_ASSOC);
$total_rows = $stmt->rowCount();
if($total_rows > 0){
foreach($row as $item){
echo '<td>'. $item['title'] .'</td>';
}
}else{
echo 'no results';
}
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