I'd like to add a print("something") if the checker turns out to be false for every item in the a_list. I'm VERY grateful for any help I can get!
def checker(lst, lstA):
for i in range(4):
if function(lst[i],lstA) != lst[i][1]: #testing FALSEHOOD
return False;
return True;
def main(???):
for H in range(0,len(a_list)):
if a_list[H] > lst[3][0]:
continue
lstA = [a_list[H]]
if not checker(lst,lstA):
continue
lstA.append(input('some input from the user'))
other_function(lstA)
if lstA[1]== 40:
print ('something something')
return #break out of EVERY loop
Your question is a little vauge, so I am not 100% positive I am actually answering the question you were asking. Also, I am guessing the code was supposed to be indented in the following way:
def main(???):
for H in range(0,len(a_list)):
if a_list[H] > lst[3][0]:
continue
lstA = [number_list[i]]
if not checker(lst,lstA):
continue
lstA.append(input('some input from the user'))
other_function(lstA)
if lstA[1]== 40:
print ('something something')
return #break out of EVERY loop
Also, you use the variable i
, which does not seem to be defined anywhere.
You could add a variable outside of the for loop keeping track of if the check has been false for all values so far. In the beginning this should be True:
...
false_for_all = True
for H in range(0,len(a_list)):
...
Then, if the check succeeds you set it to False.
...
if not checker(lst,lstA):
continue
false_for_all = True
...
Now you can use the false_for_all
variable to check if the check failed for all values.
I don't understand where you want to add print("something") . If you want to add the statement in the checker
function, you may add an indicator to store how many times the check fails:
def checker(lst, lstA):
errors = 0
for i in range(4):
if function(lst[i],lstA) != lst[i][1]: #testing FALSEHOOD
errors += 1
if not errors:
return True
elif errors == 4:
# print something here
return False
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