PHP use “use” of the interface over concrete classes

Question

Have encountered an issue I can't seem to figure out now by myself.

Using Symfony autoload module.

Here's my factory:

namespace Core\Factories;

use \Core\Gateway;

class DatabaseAccessFactory {
    // Define client type
    const DEF = 'mongo';

    public function createObject($type) {
        switch($type) {
            case self::DEF:
                return new MongoClientGateway();
                break;

            default:
                return false;
        }
    }
}

Example of /Core/Gateway/MongoClientGateway.php

<? namespace Core\Gateway;

class MongoClientGateway implements MongoDbGateway {
    public function setUp(){

    }

    public function query(){

    }

    public function save(){

    }
}

So, basically I'm using "use" keyword to load gateway namespace into my current one, and then I try to instantiate a class that is under \\Core\\Gateway namespace, but it says class is not found. Am I missing something?

Answer 1

You need to specifcy the class as well

use Core\Gateway\MongoClientGateway

or access the class with the namespace you used

new Gateway\MongoClientGateway

Btw, there's no need for the first "\\" in use \\Core\\Gateway

Answer 2

1. It's use Foo\\Bar , without leading backslash.
2. use Foo\\Bar does not mean that every Class implicitly resolves to Foo\\Bar\\Class now. use Foo\\Bar is shorthand for use Foo\\Bar as Bar , so you can reference the namespace Foo\\Bar using merely Bar . use is not "importing a namespace" , it's aliasing a namespace to a shorter name.
3. Therefore you need to write Gateway\\MongoClientGateway , or use Core\\Gateway\\MongoClientGateway explicitly if you want to be able to write just MongoClientGateway .

Answer 3

you used "use" wrong. waht "use" does, is to tell your code where class comes from.

sample code:

use \my\namespace\className

new ClassName();

this will make the className accassible without a namespace.