Bash - Calculate the Average of Numbers Inputted

Question

Need help with Linux Bash script. Essentially, when run the script asks for three sets of numbers from the user and then calculates the numbers inputted and finds the average.

#!/bin/bash
echo "Enter a number: "
read a
   while [ "$a" = $ ]; do

echo "Enter a second set of numbers: "
read b
b=$
   if [ b=$ ]

Am I going about this wrong?

Answer 1

Still not sure what you want a to be. But I think you can just loop 3 times. Then each iteration get a set of numbers, and add them up and keep track of how many you have. So something like below. (note $numbers and $sum are initialized to 0 automatically)

#!/bin/bash    
sum=0
numbers=0
for a in {1..3}; do
  read -p $'Enter a set of numbers:\n' b
  for j in $b; do
    [[ $j =~ ^[0-9]+$ ]] || { echo "$j is not a number" >&2 && exit 1; } 
    ((numbers+=1)) && ((sum+=j))
  done
done

((numbers==0)) && avg=0 || avg=$(echo "$sum / $numbers" | bc -l)
echo "Sum of inputs = $sum"
echo "Number of inputs = $numbers"
printf "Average input = %.2f\n" $avg                               

Where example output would be

Enter a set of numbers: 
1 2 3
Enter a set of numbers: 
1 2 3
Enter a set of numbers: 
7
Sum of inputs = 19
Number of inputs = 7
Average input = 2.71

Answer 2

If I understood you correctly, the following code will do what you asked:

#!/bin/bash
echo "Enter three numbers:"
read a b c
sum=$(($a + $b + $c))
count=3
result=$(echo "scale=2; 1.0 * $sum / $count" | bc -l)
echo "The mean of these " $count " values is " $result

Note - I left count as a separate variable so you can easily extend this code.

The use of bc allows floating point arithmetic (not built in to bash); scale=2 means "two significant figures".

Sample run:

Enter three numbers:
3 4 5
The mean of these  3  values is  4.00

Answer 3

Test values:

    sum=200232320
    total=300123123

Basic take average and get percentage:

    avg=$(echo "$sum / $total" | bc -l)
    avg=$(echo "$avg*100" | bc -l)
    printf "Average input = %.2f\n" $avg

Basic take average and get percentage with fault tolerance:

    # -- what if sum=0 or greater than total?
    if [ $sum -eq 0 ] || [ $sum -gt $total ] ;then
        avg=0
    else
        avg=$(echo "$sum / $total" | bc -l)
        avg=$(echo "$avg*100" | bc -l)
    fi

    printf "Average input = %.2f\n" $avg

Basic take average and get percentage:

    result=$(echo "scale=6; 1.0 * $sum / $total*100" | bc -l)
    printf "Average input = %.2f\n" $result

Basic take average and get percentage:

    result=$(echo "scale=6; 1.0 * $sum / $total*100" | bc -l) 
    printf "Average input = %.2f\n" $result

Basic take average and get percentage (with tolerance:

    # -- if sum is greater than total we have a problem add in 1.0 to address div by zero
    [[ $sum -gt $total ]] && result=0 || result=$(echo "scale=6; 1.0 * $sum / $total*100" | bc -l) 
    printf "Average input = %.2f\n" $result

output:

    ./test.sh 
    Average input = 66.72
    Average input = 66.72
    Average input = 66.72
    Average input = 66.72

Answer 4

 #!/bin/bash

echo "Enter size"

read s  `#reading size of the average`

i=1          `#initializing` 

sum=0        `#initializing`

echo "Enter the factors"

while [ $i -le $s ]

do
  read factors

sum=$((sum + factors))

i=$((i + 1))

done

avg=$(echo $sum / $s | bc -l)


   echo "Average of factors is" $avg