In C the following horror is valid:
myFunc()
{
return 42; // return type defaults to int.
}
But, what about in C++? I can't find a reference to it either way...
My compiler (Codegear C++Builder 2007) currently accepts it without warning, but I've had comments that this is an error in C++.
It's ill-formed in C++. Meaning that it doesn't compile with a standard conforming compiler. Paragraph 7.1.5/4 in Annex C of the Standard explains the change "Banning implicit int".
Implicit return types are valid in C89, but a lot of compilers warn about it.
They are not valid in C++, nor in C99.
So, it's definitely 'ill formed' C++, but it seems many compilers accept it with a warning at best.
Please add to/correct this list!
这不是合法的C ++,但是一些编译器会以静默方式或使用诊断方式接受它。
As posted, it is ill-formed. MSVC 8 gives the following error:
error C4430: missing type specifier - int assumed. Note: C++ does not support default-int
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