In my php program, I have to insert variables into one of my sql tables. Every time I go to test this out though, the values don't get posted to the table. Is there something wrong with these statements? or is the problem bigger than these 2 lines
$sqli = mySQLi_connect("localhost","root","root","myProject");
mysqli_query("insert into purchases (id, productID, quantity) values ($id, $productID, $quantity)");
Try it by using
mysqli_query("insert into purchases (id, productID, quantity) values ('$id', '$productID', '$quantity')");
you are missing a single quotes in those variables
If you use mysqli_query in a procedural way, you need to use the connection as your first parameter like this
mysqli_query($sqli, "insert into purchases (id, productID, quantity)
values ($id, $productID, $quantity)");
Otherwise you can use it in an OOP manner like this:
$sqli->query("insert into purchases (id, productID, quantity)
values ($id, $productID, $quantity)");
If you turned on error reporting on your code, you should have figured out the problem as the following warning is produced:
PHP Warning: mysqli_query() expects at least 2 parameters, 1 given in /home/jkiang/test.php on line 10
First, you are mixing your procedural and your object oriented mysqli. Second, you have no error checking. Without knowing what your variables contain I suggest you try something like this:
$sqli = new mysqli_connect("localhost","root","root","myProject");
if($sqli->connect_errno > 0){
die("Connection couldn't be established");
}
$q = "insert into purchases (id, productID, quantity) values ($id, $productID, $quantity)";
if(!$result = $sqli->query($q)){
die("There was an error with your query");
}
$sqli->close();
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