I have an application which will ALWAYS be run in only one single time zone, so I do not need to worry about converting between time zones. However, the datetime must always be printed out in the following format:
yyyy-MM-dd hh.mm.ss
The code below fails to print the proper format:
public void setCreated(){
DateTime now = new org.joda.time.DateTime();
String pattern = "yyyy-MM-dd hh.mm.ss";
created = DateTime.parse(now.toString(), DateTimeFormat.forPattern(pattern));
System.out.println("''''''''''''''''''''''''''' created is: "+created);
}
The setCreated() method results in the following output:
"2013-12-16T20:06:18.672-08:00"
How can I change the code in setCreated() so that it prints out the following instead:
"2013-12-16 20:06:18"
You aren't parsing anything, you are formatting it. You need to use DateTimeFormatter#print(ReadableInstant)
.
DateTime now = new org.joda.time.DateTime();
String pattern = "yyyy-MM-dd hh.mm.ss";
DateTimeFormatter formatter = DateTimeFormat.forPattern(pattern);
String formatted = formatter.print(now);
System.out.println(formatted);
which prints
2013-12-16 11.13.24
This doesn't match your format, but I'm basing it on your code, not on your expected output.
public static void main(String args[])
{
SimpleDateFormat sdfDate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");//dd/MM/yyyy
Date now = new Date();
String strDate = sdfDate.format(now);
System.out.println(strDate);
}
out put 2013-12-17 09:48:11
try this
SimpleDateFormat sdfDate = new SimpleDateFormat("yyyy-MM-dd HH.mm.ss");
Date now = new Date();
String strDate = sdfDate.format(now);
System.out.println(strDate);
Try this:
org.joda.time.DateTime now = new org.joda.time.DateTime();
String pattern = "yyyy-MM-dd hh.mm.ss";
DateTimeFormatter formatter = DateTimeFormat.forPattern(pattern);
String formatted = formatter.print(now);
LocalDateTime date = formatter.parseLocalDateTime(formatted);
System.out.println(date.toDateTime());
现在在Java 9中,您可以使用:
LocalDateTime.now().format(DateTimeFormatter.ofPattern("yyyy-MM-dd hh.mm.ss"));
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