Java IllegalArgumentException Illegal character in query at index

Question

I'm using the code below, which works fine when I use http://stackoverflow.com/ . When I change it to http://www.sitetest.com/query.php?request=how are you My app throws an exception. It says:

Caused by: java.lang.IllegalArgumentException: Illegal character in query at index 46: http://www.sitetest.com/query.php?request=how %20are%20you?

What is the Illegal Character in there? I can't spot it.

  AsyncTask<String, String, String> result = new RequestTask().execute("http://www.sitetest.com/query.php?request=how are you"); 
        try { 
            this.textToSpeech(result.get().trim());
        } catch (InterruptedException e) { 
            //e.printStackTrace();
            Toast.makeText(this, "Interrupted",
                    Toast.LENGTH_LONG).show();
        } catch (ExecutionException e) { 
            Toast.makeText(this, e.getMessage(),
                    Toast.LENGTH_LONG).show();
            //e.printStackTrace();
        }

 12-22 19:17:32.547: E/AndroidRuntime(20764): FATAL EXCEPTION: AsyncTask #1 12-22 19:17:32.547: E/AndroidRuntime(20764): java.lang.RuntimeException: An error occured while executing doInBackground() 12-22 19:17:32.547: E/AndroidRuntime(20764): at android.os.AsyncTask$3.done(AsyncTask.java:299) 12-22 19:17:32.547: E/AndroidRuntime(20764): at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:352) 12-22 19:17:32.547: E/AndroidRuntime(20764): at java.util.concurrent.FutureTask.setException(FutureTask.java:219) 12-22 19:17:32.547: E/AndroidRuntime(20764): at java.util.concurrent.FutureTask.run(FutureTask.java:239) 12-22 19:17:32.547: E/AndroidRuntime(20764): at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230) 12-22 19:17:32.547: E/AndroidRuntime(20764): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1080) 12-22 19:17:32.547: E/AndroidRuntime(20764): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:573) 12-22 19:17:32.547: E/AndroidRuntime(20764): at java.lang.Thread.run(Thread.java:856) 12-22 19:17:32.547: E/AndroidRuntime(20764): Caused by: java.lang.IllegalArgumentException: Illegal character in query at index 46: http://www.sitetest.com/query.php?request=how %20are%20you? 12-22 19:17:32.547: E/AndroidRuntime(20764): at java.net.URI.create(URI.java:727) 12-22 19:17:32.547: E/AndroidRuntime(20764): at org.apache.http.client.methods.HttpGet.<init>(HttpGet.java:75) 12-22 19:17:32.547: E/AndroidRuntime(20764): at com.sitetest.chat.MainActivity$RequestTask.doInBackground(MainActivity.java:170) 12-22 19:17:32.547: E/AndroidRuntime(20764): at com.sitetest.chat.MainActivity$RequestTask.doInBackground(MainActivity.java:1) 12-22 19:17:32.547: E/AndroidRuntime(20764): at android.os.AsyncTask$2.call(AsyncTask.java:287) 12-22 19:17:32.547: E/AndroidRuntime(20764): at java.util.concurrent.FutureTask.run(FutureTask.java:234) 12-22 19:17:32.547: E/AndroidRuntime(20764): ... 4 more 

Answer 1

Seems you have some whitespace character there which is not the regular
space character (decimal 32). Also, it seems it is not URL encoded.

Answer 2

You should have inside the execute sth like:

urlencode('http://www.sitetest.com/query.php?request=how are you')

So, complete code on that line:

AsyncTask<String, String, String> result = new RequestTask().execute(urlencode('http://www.sitetest.com/query.php?request=how are you'));

My source:

PHP URL Encoding / Decoding

Side note:

I don't have a php environment installed on my machine right now, the verifying of that function needs to be made by you. That's what I found.