Error of XSLT with Eclipse Kepler
Question
I wrote two files
The first file is NewFile.xml(I wrote <?xml-stylesheet type="text/xsl" href="NewStylesheet.xsl"?> in this file) and The second file is NewStylesheet.xsl(Although I do not think there are errors in xsl file, I posted it anyways):
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>My CD Collection</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th align="left">Title</th>
<th align="left">Artist</th>
</tr>
<xsl:for-each select="catalog/cd">
<tr>
<td><xsl:value-of select="title"/></td>
<td><xsl:value-of select="artist"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
However, when I run "XSL Transformation" The error occurs:
15:55:02,242 INFO [main] Main - javax.xml.transform.TransformerFactory=null
15:55:02,243 INFO [main] Main - java.endorsed.dirs=/System/Library/Java/JavaVirtualMachines/1.6.0.jdk/Contents/Home/lib/endorsed
15:55:02,245 INFO [main] Main - launchFile: /Users/xuxu/Documents/workspace/.metadata/.plugins/org.eclipse.wst.xsl.jaxp.launching/launch/launch.xml
15:55:02,299 ERROR [main] JAXPSAXProcessorInvoker - Could not compile stylesheet
15:55:02,300 ERROR [main] JAXPSAXProcessorInvoker - Could not compile stylesheet
javax.xml.transform.TransformerConfigurationException: Could not compile stylesheet
at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerFactoryImpl.newTemplates(TransformerFactoryImpl.java:886)
at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerFactoryImpl.newTransformer(TransformerFactoryImpl.java:669)
at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerFactoryImpl.newTransformerHandler(TransformerFactoryImpl.java:961)
at org.eclipse.wst.xsl.jaxp.debug.invoker.internal.JAXPSAXProcessorInvoker.addStylesheet(JAXPSAXProcessorInvoker.java:136)
at org.eclipse.wst.xsl.jaxp.debug.invoker.internal.JAXPSAXProcessorInvoker.transform(JAXPSAXProcessorInvoker.java:210)
at org.eclipse.wst.xsl.jaxp.debug.invoker.internal.JAXPSAXProcessorInvoker.transform(JAXPSAXProcessorInvoker.java:186)
at org.eclipse.wst.xsl.jaxp.debug.invoker.internal.Main.main(Main.java:73)
Caused by: java.io.FileNotFoundException: /Applications/eclipse/Eclipse.app/Contents/MacOS/NewStylesheet.xsl (No such file or directory)
at java.io.FileInputStream.open(Native Method)
Why it says that Caused by: java.io.FileNotFoundException: /Applications/eclipse/Eclipse.app/Contents/MacOS/NewStylesheet.xsl (No such file or directory) ? Any help here?
1 answers
solution1
1 ACCPTED 2014-01-08 08:08:54
The current directory when the transformation runs in the Eclipse install directory not the directory containing the files so The href="NewStylesheet.xsl" is looking in the wrong place.
According to this Tutorial you do not put a <?xml-stylesheet in the XML file. Just right click on the XSL file and select XSL Transformation .
This documentation says that you can select a XSL file and a XML file. It also says you can use the Run Configuration to configure what XSL to use for a XML file.
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