Although I am able to create stored procedure successfully I am getting "TRANSACTION BEGIN END MISMATCH"
error upon using it. The stored Procedure works fine when I remove transaction.
ALTER PROCEDURE Proc_LoanRepayment @LASAcctno [VARCHAR] (15),
@EntryDate [VARCHAR] (8),
@ValueDate [VARCHAR] (8),
@ModeofPayment VARCHAR(20),
@ChqNo VARCHAR(20),
@ChqDate VARCHAR(8),
@ChqAmt MONEY,
@CstBnkNo VARCHAR(20),
@Cstbnkid VARCHAR(20),
@CmpBnkNo VARCHAR(20),
@Cmpbnkid VARCHAR(20),
@Narration1 [VARCHAR] (100),
@Narration2 [VARCHAR] (100),
@EntryType VARCHAR(30),
@PostingString [VARCHAR] (max)
AS
BEGIN TRAN
DECLARE @string AS VARCHAR(max)
DECLARE Cur_A CURSOR FOR
SELECT *
FROM dbo.split(@PostingString, ',')
OPEN Cur_a
FETCH NEXT FROM cur_a INTO @string
WHILE @@FETCH_STATUS = 0
BEGIN
IF ( object_id('TempDB..#Temp') ) IS NOT NULL
BEGIN
DROP TABLE #Temp
END
-- declare @temp table (srno int identity,items varchar(max))
SELECT *
INTO #temp
FROM dbo.Split(@string, '|')
DECLARE @LoanNo AS VARCHAR(20),
@BankAcct AS VARCHAR(20),
@TDS AS MONEY,
@LASPAC AS MONEY,
@INTRND AS MONEY,
@INTRAC AS MONEY,
@STAXPLRVL AS MONEY,
@PNLINT AS MONEY,
@OVRDUEINT AS MONEY,
@STMPDTYRVL AS MONEY,
@PROFESRVL AS MONEY,
@DOCCHGRVL AS MONEY,
@CHQBNCRVL AS MONEY
ALTER TABLE #temp
ADD srno INT IDENTITY
SELECT @LoanNo = items
FROM #temp
WHERE srno = 1
SELECT @bankAcct = items
FROM #temp
WHERE srno = 2
SELECT @TDS = items
FROM #temp
WHERE srno = 3
SELECT @LASPAC = items
FROM #temp
WHERE srno = 4
SELECT @INTRND = items
FROM #temp
WHERE srno = 5
SELECT @INTRAC = items
FROM #temp
WHERE srno = 6
SELECT @STAXPLRVL = items
FROM #temp
WHERE srno = 7
SELECT @PNLINT = items
FROM #temp
WHERE srno = 8
SELECT @OVRDUEINT = items
FROM #temp
WHERE srno = 9
SELECT @STMPDTYRVL = items
FROM #temp
WHERE srno = 10
SELECT @PROFESRVL = items
FROM #temp
WHERE srno = 11
SELECT @DOCCHGRVL = items
FROM #temp
WHERE srno = 12
SELECT @CHQBNCRVL = items
FROM #temp
WHERE srno = 13
INSERT INTO Tbl_BankEntry
(LASAcctno,
EntryDate,
ValueDate,
ModeofPayment,
ChqNo,
ChqDate,
ChqAmt,
CstBnkNo,
Cstbnkid,
CmpBnkNo,
Cmpbnkid,
Narration1,
Narration2,
LoanNo,
BankAcct,
TDS,
LASPAC,
INTRND,
INTRAC,
STAXPLRVL,
PNLINT,
OVRDUEINT,
STMPDTYRVL,
PROFESRVL,
DOCCHGRVL,
CHQBNCRVL,
status,
mkrdt,
mkrid,
EntryType)
VALUES ( @LASAcctno,
@EntryDate,
@ValueDate,
@ModeofPayment,
@ChqNo,
@ChqDate,
@ChqAmt,
@CstBnkNo,
@Cstbnkid,
@CmpBnkNo,
@Cmpbnkid,
@Narration1,
@Narration2,
@LoanNo,
@BankAcct,
@TDS,
@LASPAC,
@INTRND,
@INTRAC,
@STAXPLRVL,
@PNLINT,
@OVRDUEINT,
@STMPDTYRVL,
@PROFESRVL,
@DOCCHGRVL,
@CHQBNCRVL,
'P',
GETDATE(),
'c97176',
@EntryType )
FETCH NEXT FROM Cur_a INTO @string
END
CLOSE cur_a
DEALLOCATE cur_a
RETURN
COMMIT TRAN
Your RETURN
statement is before your COMMIT
statement.
Suggest you look into @Martin Smith's sugegstion of using table valued parameters rather than splitting strings (SQL Server 2008+), and @ Damien_The_Unbeliever's suggestion of the expected ordering.
Also, try to rewrite procedure so that it doesn't require a cursor, and that you do the least amount possible of work inside the transaction.
Also, look at TRY/CATCH
and checking whether there is an active transaction ( @@TRANCOUNT
) before commiting.
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