Defining Variable Within if/fi statement In A Unix Bash Script

Question

Good Morning All,

Currently, I am trying to define a variable within an if/fi statement in a bash script that checks the current system time and as a result of the current system time, defines a variable:

TIME=`date +%h%m%s`

if [ ${TIME} -ge 050000 ]; then RUNHR=00 fi
if [ ${TIME} -ge 110000 ]; then RUNHR=06 fi
if [ ${TIME} -ge 170000 ]; then RUNHR=12 fi
if [ ${TIME} -ge 225900 ]; then RUNHR=18 fi

After I do this however, the RUNHR value doesn't stick and is never defined.

Does anyone have any ideas how to fix this?

Answer 1

Linux Scripting is not syntax flexible.

first of all you must use HM rather hm , small hm will give you date in string.

This is tested.

TIME=`date +%H%M%s`

if [ ${TIME} -ge 050000 ]; then 
RUNHR=00 
fi
if [ ${TIME} -ge 110000 ]; then 
RUNHR=06 
fi
if [ ${TIME} -ge 170000 ]; then 
RUNHR=12 
fi
if [ ${TIME} -ge 225900 ]; then 
RUNHR=18 
fi

echo $RUNHR

Thanks

Suyash Jain
http://linuxhacks.in